Use the two points given by the rides: $(4,13)$ and $(10,22)$. First find the slope:

Then use $y=mx+b$ with $(4,13)$:

so $b=7$. Therefore the linear model is

First find the slope:

So the line has the form $y=-2x+b$. Substitute one of the given points, such as $(3,11)$:

Therefore, the slope-intercept form is

which is equivalent to the equation of the line.

The line passes through $(0,6)$, so its $y$-intercept is $6$. That means the equation must have the form $y=mx+6$. Next, use the two given points to find the slope:

So the equation is

Since the line is $y=ax+4$, substitute the point $(6,-2)$ to find $a$:

So the equation of the line is $y=-x+4$. Checking the statements, when $x=3$, the value of $y$ is

so $(3,1)$ is on the line. That statement must be true.

First find the slope of the line through $(4,0)$ and $(28,6)$:

So the equation has the form $y=\frac{1}{4}x+b$. Substitute the point $(4,0)$:

so $b=-1$. Therefore, the equation is